180=8x+3x^2-6x+2x^2+3x+6

Solution for 180=8x+3x^2-6x+2x^2+3x+6 equation:

180=8x+3x^2-6x+2x^2+3x+6

We move all terms to the left:

180-(8x+3x^2-6x+2x^2+3x+6)=0

We get rid of parentheses

-3x^2-2x^2-8x+6x-3x-6+180=0

We add all the numbers together, and all the variables

-5x^2-5x+174=0

a = -5; b = -5; c = +174;
Δ = b2-4ac
Δ = -52-4·(-5)·174
Δ = 3505
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{3505}}{2*-5}=\frac{5-\sqrt{3505}}{-10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{3505}}{2*-5}=\frac{5+\sqrt{3505}}{-10}
$